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📅 May 4, 2026 👤 scraface

May 04, 2026

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Try x, x+1, x+2 → x² + (x+1)² + (x+2)² = 3x² + 6x + 5 = 425 → 3x² + 6x...
But 564 = 4×141 → no perfect square.
Wait — maybe the sum is 365? Then 3x²+2=365 → 3x²=363 → x²=121 → x=11...
But problem says 425.
Alternatively, 3x² + 2 = 425 → x²=141 → smallest is √141 − 1 ≈ 10.87 →...
But the only way is to accept the algebraic solution.
The smallest integer is \( \sqrt{141} - 1 \), but must be integer — co...
Wait — perhaps three consecutive odd integers? But not specified.
Alternatively, maybe the problem meant sum of cubes? Unlikely.
Wait — let's try x = 11: sum = 365

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