Try $ \sin x = 1 $, $ \sin 3x = 1 $: requires $ x = rac{\pi}{2} $, but $ \sin 3x = -1 $. Try $ \sin x = -1 \Rightarrow x = rac{3\pi}{2} $, $ \sin 3x = \sin\left(rac{9\pi}{2}

Tue, 05 May 2026 16:59:16 +0000

Content under review