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Home » Page Break Game-Changer: Transform Readers Experience Forever (Shock Test Inside!) - All Square Golf

Page Break Game-Changer: Transform Readers Experience Forever (Shock Test Inside!) - All Square Golf

📅 May 2, 2026 👤 scraface

May 02, 2026

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\sum_{k=1}^{10} k^3 = \left( \frac{10 \cdot 11}{2} \right)^2 = (55)^2...
Now compute $ 3025 \mod 7 $. First, reduce 55 modulo 7:
\div 7 = 7 \text{ remainder } 6 \Rightarrow 55 \equiv 6 \pmod{7}
\Rightarrow 55^2 \equiv 6^2 = 36 \equiv 1 \pmod{7}
Alternatively, $ 3025 \div 7 = 432 \text{ remainder } 1 $, so $ 3025 \...
Therefore, the remainder is $ \boxed{1} $.
Question: What is the greatest common divisor of $ 2^{12} - 1 $ and $...
Solution: We use the identity:
\gcd(2^a - 1, 2^b - 1) = 2^{\gcd(a,b)} - 1
Here, $ a = 12 $, $ b = 18 $, so $ \gcd(12, 18) = 6 $.

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