But this counts selections per row order — since we are selecting unordered triples, we must divide by \( 3! = 6 \) only if order doesn’t matter. However, since we are selecting positions and the grid is fixed, each position is unique, and choosing one per row from 3 distinct rows gives \( 3^3 = 27 \) per set of 3 rows.

Wed, 06 May 2026 03:51:45 +0000

Content under review