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how many tbsp in cup - All Square Golf

📅 May 2, 2026 👤 scraface

May 02, 2026

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📌 \( ac + cd = c(a + d) = 0 \)

📌 This implies either \( b = 0 \) and \( c = 0 \), or \( a + d = 0 \).

📌 Case 1:** \( b = 0 \) and \( c = 0 \)

📌 Then, \( a^2 = 1 \) and \( d^2 = 1 \). So, \( a = \pm 1 \) and \( d = \pm 1 \). The diagonal matrices \( egin{pmatrix} \pm 1 & 0 \ 0 & \pm 1 \end{pmatrix} \) satisfy \( T^2 = I \).

📌 Case 2:** \( a + d = 0 \)

📌 Let \( d = -a \). Substituting into equations 1 and 4:

📌 \( bc + a^2 = 1 \)

📌 Both equations are identical. So, \( a^2 + bc = 1 \) holds. Thus, the conditions are \( d = -a \) and \( a^2 + bc = 1 \).

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Question: A space explorer collects crystals from three moons, each yi...
Solution: We find $ \gcd(72, 108, 180) $.
First, factor each number:
$ 72 = 2^3 \cdot 3^2 $
$ 108 = 2^2 \cdot 3^3 $
$ 180 = 2^2 \cdot 3^2 \cdot 5 $
Take the lowest powers of common primes:
$ 2^2 $ and $ 3^2 $
So $ \gcd = 4 \cdot 9 = 36 $

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