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how do you spell omelette - All Square Golf

📅 May 5, 2026 👤 scraface

May 05, 2026

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📌 A historian analyzing early computer blueprints finds that the ENIAC used 20 decimal digits of memory per register and had 10 registers. Later, a STOR-MATAC system improved this to 16 binary registers (2 bytes each) for the same effective capacity. How many total bytes does the ENIAC register memory occupy compared to the improved system?

📌 ENIAC: 20 digits × 10 registers = 200 decimal digit equivalents. Assuming 1 decimal digit ≈ 0.055 bytes (approx 4-bit) → 200 × 0.055 = 11 bytes (exact: 20 × 10 × 0.055 = 11)

📌 But better: if 1 register = 20 digits = 200 bits = 25 bytes, then 10 registers = 10 × 25 = <<10*25=250>>250 bytes

📌 Improved system: 16 registers × 2 bytes each = <<16*2=32>>32 bytes

📌 Difference: 250 – 32 = <<250-32=218>>218 bytes

📌 But question asks how many bytes the ENIAC uses — assuming phrased as direct: ENIAC uses 250 bytes (20 digits × 10 registers × 0.055 ≈ 11)? Wait — standard interpretation: ENIAC’s memory equivalent:

📌 Use: 20 digits ≈ 20 × 4 = 80 bits per register → 8 bytes

📌 registers → 10 × 8 = 80 bytes per register? Too high.

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Both values satisfy the equation. Thus, the values of \(t\) are:
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