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📰 But $ a^2 - b^2 = (a - b)(a + b) $, and $ a^2 + b^2 = (a + b)^2 - 2ab $. Instead, observe $ S = rac{2(a^2 + b^2)}{a^2 - b^2} $. Let $ a = 1 $, $ b = i $: 📰 S = rac{2(1 + (-1))}{1 - (-1)} = 0. 📰 But earlier steps suggest $ S = rac{2(a^2 + b^2)}{a^2 - b^2} $. For $ |a| = |b| = 1 $, $ a^2 \overline{a}^2 = 1 $, so $ a^2 = rac{1}{\overline{a}^2} $. This path is complex. Instead, let $ a = 1 $, $ b = -1 $: $ S = rac{0}{2} + rac{2}{0} $, invalid. Correct approach: Let $ a = e^{i heta} $, $ b = e^{i\phi} $, then 📰 Wie Viele Einzigartige Paare Von Genen Gibt Es 8618954 📰 Batman Vs Teenage Mutant Ninja Turtles Which Hero Wins In An Epic Clash 782906 📰 This Simple Tip Reveals Your Exact Windows System Instantlydont Miss Out 9067112 📰 Your Nearby Halal Meat Is Hiding In Plain Sightdont Miss Out Now 3247256 📰 Light Blue Bg Ideas Thatll Save You Hours Of Design Work 5825589 📰 Watch The Happening 3145945 📰 How To Say And In Spanish 6168326 📰 Why Every Nonprofit Needs Microsoft 365 Business Premiumcex Power Up Your Workflow 1356254 📰 Release Jordans Today 6283174 📰 Mcchicken Calories 79509 📰 The Lincoln Memorial Washington 8965737 📰 Paint Mac Os 552396 📰 This The Boys Comic Plot Twist Shocked Fansare You Ready For The Truth 8615420 📰 The True Death Toll Of Flu Each Year How Many Will Never Come Back 3620344 📰 H Ureolysis With Nitrifier Consortia 7421139