But since 506 ≠ 0, no solution has \(y = 0\) (would require \(m = n\), \(m^2 = 506\), not square), so all solutions come in pairs \((x,y)\) and \((x,-y)\), except if \(y = 0\), which doesn’t occur.

Tue, 05 May 2026 17:34:14 +0000

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