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📅 May 4, 2026 👤 scraface

May 04, 2026

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Thus, the equation \( x^3 - 4x + 2 = 0 \) has three real solutions, ex...
But to give **exact real solutions**, we use:
Let \( x = 2\cos\theta \). Then:
Using identity: \( 4\cos^3\theta - 3\cos\theta = \cos 3\theta \), but...
Try substitution: \( x = 2y \):
Let \( y = \cos\theta \), then:
4\cos^3\theta - 4\cos\theta + 1 = 0 \implies \cos 3\theta = \frac{1}{4...
Using identity: \( \cos 3\theta = \frac{1}{4} \implies 3\theta = \pm \...
\theta = \frac{1}{3} \arccos\left(\frac{1}{4}\right),\quad \frac{1}{3}...
So the three real solutions for \( y \) are:

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